Symmetric equations of the light quantum systems

This is explained in the article: <Using metric views to establish special relativity>, the oscillating energy of the light quantum system of a particle is the result of Lorentz transformation. For the light quantum system of a free particle, the particle must have vibration energy when observed in the coordinate system of relative motion of the particle.

Conversely, when vibration energy is observed, there must be a relative motion between the particle and the coordinate system.

The coordinate system is a rest system. Suppose the coordinate systemis the relative rest coordinate system of particle. is the center of particle

 

. Coordinate system is moving with respect to coordination system  at velocity . From the  system, particleis in vibration state, and the

 

vibration frequency is

 

Take small volume elements in the region around the center of the particle. , and momentum

 

  is the velocity of the particle, constant in the volume element. The subscript “ f ” indicates the reading measured by the flat metric.

The subscript “c” indicates the reading measured by the curved metric.

In the region around the center of the particle, the distribution of matter is not uniform, the velocity of the light quantum of the particle is

 

, and the vibration energy is.

     

is the reading of density of the light quantum measured by the flat metric, which is a constant.  is the reading of velocity of the particle

 

 measured by the curved metric.

 

 

In higher mathematics there is a function, ,.

 

 

From the point of view of classical mechanics, the mass of a particle is concentrated at the center of the particle: .      The mass of

 

 a particle from the perspective of the de Broglie hypothesis in quantum mechanics is . This is .

 

 It can be seen from the formula that and can replace each other under the integral symbol. And what we get is the classical value of the whole particle at point 0 as measured by the curve metric.

 

 

According to the formula we can get: under the integral sign , and can be substituted for each other. And what we get is the classical value of the density of light quantum of whole particle at point 0 as measured by the curve metric.

 

 

According to the formula so once again we can get:

 

and  all are the classical values of the whole particle at point 0 as measured by the curve metric.

 

 

Similarly, for any function,

 

we can have: .

 is the classical value of the whole particle at point 0 as measured by the curve metric. Let’s call this principle as  principle, and we’ll use it a

 lot in the future.

 

Now let’s talk about the vibrational frequencies of a particle. Already mentioned above: In the region around the center of the particle, the vibrational

 

 energy of light quantum is . For the whole particle:

 

 

 


In the formula is the radius of curvature of the curvature line on the distributing surface of light quantum. The above principle is used in the

 derivation. Among them, all are the classical values of the whole particle at point 0 according to the

 

principle. is an equiprobability vector. Take the radius vector of the coordinate system as the axis of the local coordinate system, we can get

 

 . is a constant said above. Take , then get .

 

 

Now back to quantum mechanics, where the state function of a free particle is . But now there is

 

 

 . Need to introduce “auxiliary momentum” . Let ,. is the mass of the particle.

 

 

After introducing “auxiliary momentum” , Quantum mechanics has

 

 

.

 

 

Among, , .

 

 

Similarly.

 

 

Among them, , .

 

 

Take , . So From the equation above we can get.

 

 

  The state function of a free particle is: ,  

 

 

, ,

 

 

 The above are there has been , and  above,

 

 

 

 

 

From the equation above

 

 

 

 

There has been, so get: . Hence the wave equation for the particle we have gotten is

 

 

, among it .

 

 

Free particles are spherically symmetric. It can be expressed in spherical coordinates. In terms of spherical coordinates, can get: ,

 

 . Choose the appropriate units that can be considered . Takethen the wave equation is

 

 

Where is the third component of the angular momentum quantum number which corresponds to the charge of particle.

Equation (1is the wave equation of free particle. Equation2is the wave equation of free particle in spherical coordinate system.

 

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